Help with image

[Peter C. Russell]

I was looking at this image trying to determine the different temperature through out this storm and was wondering if I could get some help.

On my screen I can't really see the upper right hand corner or the designation for B or T.

I thought this would be interesting to talk about.

http://www.goes.noaa.gov/ECIR4.html

[Peter C. Russell]

With the help of Bill Warner, I think I have figured this out.


The temperature on the Nevada/ Utah border is -23.15

B= 200
T=418
T - B = 218 - 273.15 = -55.15 + 32 = -23.15

How'd I do Bill?

[Peter C. Russell]

Correction

B = 200
T = 418
T - B = 218 - 273.15 = -55.15 X 1.8 = -99.27c + 32 = -67.27f

Thanks again Bill for the help.
Wish I had the elevation info.


With all the hits on this thread I'm surprised no one is interested.

I thought this would be a good exercise to convert Kelvin to celsius to farenheit.

Where's the experts that teach this stuff, moreover, where are all the thermographers who practice it.

[William Warner]

You're welcome Pete.
It is really interesting to see what the apparent temperatures of those clouds turn out to be.

[Peter C. Russell]

Thanks for your help Bill.

It is interesting and after 200+ views your the only one who responded. I would have thought that the thermographers who visit this thread would want to participate in how to convert Kelvin to Celsius to Fahrenheit. After all, isn't this what thermal imagining is all about??? Temperature. And this is a real world event that happens every day.

Surprised the educators didn't chime in.

Mr. Decker excluded.

[Chuck Evans]

Who does conversions by hand?


B = 200
T = 218 Kelvin
-55.15 Celsius
-67.27 Fahrenheit

Interesting exercise though.

[Peter C. Russell]

Originally Posted by cevans

Who does conversions by hand?


B = 200
T = 218 Kelvin
-55.15 Celsius
-67.27 Fahrenheit

Interesting exercise though.

It helps if you want to advance your knowledge and understanding of Kelvin, Celsius and Fahrenheit

Chuck, why not give it a try? Whats the temperature in upstate NY by the Canadian border?

Using image # 3 from my link on the first post.

[Chuck Evans]

Looks like the B is 195 to me in that image.


B = 195
T = 223 Kelvin
-50.15 Celsius
-58.27 Fahrenheit

Still not converting by hand though.

So what's the highest temp you see on that same image? I get about 300K

Do you know what the "B" stands for in the formula?

[ldapkus]

Try this

[Peter C. Russell]

Originally Posted by cevans

Looks like the B is 195 to me in that image.


B = 195
T = 223 Kelvin
-50.15 Celsius
-58.27 Fahrenheit

Still not converting by hand though.

So what's the highest temp you see on that same image? I get about 300K

Do you know what the "B" stands for in the formula?

B stands for brightness

Here goes.

B = 195
T = 473
T - B = (223 - 273.15) = (-50.15 X 1.8 = (-90.27) + 32 = -58.27

The clouds in the atmosphere over New York is apparently -57.27f

You got it just left out a portion of the equation. I see the brightest area over Canada, very white, around 255

[Chuck Evans]

Originally Posted by prussell

B stands for brightness

Here goes.

B = 195
T = 473
T - B = (223 - 273.15) = (-50.15 X 1.8 = (-90.27) + 32 = -58.27

The clouds in the atmosphere over New York is apparently -57.27f

You got it just left out a portion of the equation. I see the brightest area over Canada, very white, around 255

See above is why I don't do it by hand, but your math looks good.

Thanks for the definition of B, I wasn't aware.

Now would the brightest area be the warmest or coolest based on the T formula? Would you expect the warmest temps to be over Canada or Mexico? Still looking at image #3.

[Peter C. Russell]

Looking at the map and without doing the math it looks like it's warmer over Mexico.

On the brightness scale I would use 15 for Mexico and 95 for Canada